Problem
You are given a 0-indexed m x n
integer matrix grid
. The width of a column is the maximum **length **of its integers.
- For example, if
grid = [[-10], [3], [12]]
, the width of the only column is3
since-10
is of length3
.
Return an integer array ans
of size n
where ans[i]
is the width of the ith
column.
The length of an integer x
with len
digits is equal to len
if x
is non-negative, and len + 1
otherwise.
Example 1:
Input: grid = [[1],[22],[333]]
Output: [3]
Explanation: In the 0th column, 333 is of length 3.
Example 2:
Input: grid = [[-15,1,3],[15,7,12],[5,6,-2]]
Output: [3,1,2]
Explanation:
In the 0th column, only -15 is of length 3.
In the 1st column, all integers are of length 1.
In the 2nd column, both 12 and -2 are of length 2.
Constraints:
m == grid.length
n == grid[i].length
1 <= m, n <= 100
-109 <= grid[r][c] <= 109
Solution (Java)
class Solution {
public int[] findColumnWidth(int[][] grid) {
int [] arr = new int[grid[0].length];
for(int i=0; i<grid[0].length; i++){
for(int j=0; j<grid.length; j++){
arr[i] = Math.max(arr[i],String.valueOf(grid[j][i]).length());
}
}
return arr;
}
}
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).