Problem
Given the roots of two binary trees root
and subRoot
, return true
if there is a subtree of root
with the same structure and node values of subRoot
and false
otherwise.
A subtree of a binary tree tree
is a tree that consists of a node in tree
and all of this node's descendants. The tree tree
could also be considered as a subtree of itself.
Example 1:
Input: root = [3,4,5,1,2], subRoot = [4,1,2]
Output: true
Example 2:
Input: root = [3,4,5,1,2,null,null,null,null,0], subRoot = [4,1,2]
Output: false
Constraints:
The number of nodes in the
root
tree is in the range[1, 2000]
.The number of nodes in the
subRoot
tree is in the range[1, 1000]
.-10^4 <= root.val <= 10^4
-10^4 <= subRoot.val <= 10^4
Solution (Java)
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
private boolean isSubtreeFound(TreeNode root, TreeNode subRoot) {
if (root == null && subRoot == null) {
return true;
}
if (root == null || subRoot == null) {
return false;
}
if (root.val == subRoot.val) {
return isSubtreeFound(root.left, subRoot.left) && isSubtree(root.right, subRoot.right);
} else {
return false;
}
}
public boolean isSubtree(TreeNode root, TreeNode subRoot) {
if (root == null && subRoot == null) {
return true;
}
if (root == null || subRoot == null) {
return false;
}
return isSubtreeFound(root, subRoot)
|| isSubtree(root.left, subRoot)
|| isSubtree(root.right, subRoot);
}
}
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).