Problem
Given an array of integers arr
and two integers k
and threshold
, return **the number of sub-arrays of size *k
* and average greater than or equal to **threshold
.
Example 1:
Input: arr = [2,2,2,2,5,5,5,8], k = 3, threshold = 4
Output: 3
Explanation: Sub-arrays [2,5,5],[5,5,5] and [5,5,8] have averages 4, 5 and 6 respectively. All other sub-arrays of size 3 have averages less than 4 (the threshold).
Example 2:
Input: arr = [11,13,17,23,29,31,7,5,2,3], k = 3, threshold = 5
Output: 6
Explanation: The first 6 sub-arrays of size 3 have averages greater than 5. Note that averages are not integers.
Constraints:
1 <= arr.length <= 10^5
1 <= arr[i] <= 10^4
1 <= k <= arr.length
0 <= threshold <= 10^4
Solution (Java)
class Solution {
public int numOfSubarrays(int[] arr, int k, int threshold) {
int sum = 0;
for (int i = 0; i < k - 1; i++) {
sum += arr[i];
}
int count = 0;
for (int i = k - 1; i < arr.length; i++) {
sum += arr[i];
if (i - k >= 0) {
sum -= arr[i - k];
}
if (sum / k >= threshold) {
count++;
}
}
return count;
}
}
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).