Problem
Given an array of integers nums
, return **the number of *good pairs***.
A pair (i, j)
is called good if nums[i] == nums[j]
and i
< j
.
Example 1:
Input: nums = [1,2,3,1,1,3]
Output: 4
Explanation: There are 4 good pairs (0,3), (0,4), (3,4), (2,5) 0-indexed.
Example 2:
Input: nums = [1,1,1,1]
Output: 6
Explanation: Each pair in the array are good.
Example 3:
Input: nums = [1,2,3]
Output: 0
Constraints:
1 <= nums.length <= 100
1 <= nums[i] <= 100
Solution (Java)
class Solution {
public int numIdenticalPairs(int[] nums) {
int count = 0;
for (int i = 0; i < nums.length; i++) {
for (int j = i + 1; j < nums.length; j++) {
if (nums[i] == nums[j]) {
count++;
}
}
}
return count;
}
}
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).