2363. Merge Similar Items

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    Problem

    You are given two 2D integer arrays, items1 and items2, representing two sets of items. Each array items has the following properties:

    Return a 2D integer array ret where ret[i] = [valuei, weighti], with weighti **being the *sum of weights* of all items with value** valuei.

    Note: ret should be returned in ascending order by value.

      Example 1:

    Input: items1 = [[1,1],[4,5],[3,8]], items2 = [[3,1],[1,5]]
    Output: [[1,6],[3,9],[4,5]]
    Explanation: 
    The item with value = 1 occurs in items1 with weight = 1 and in items2 with weight = 5, total weight = 1 + 5 = 6.
    The item with value = 3 occurs in items1 with weight = 8 and in items2 with weight = 1, total weight = 8 + 1 = 9.
    The item with value = 4 occurs in items1 with weight = 5, total weight = 5.  
    Therefore, we return [[1,6],[3,9],[4,5]].
    

    Example 2:

    Input: items1 = [[1,1],[3,2],[2,3]], items2 = [[2,1],[3,2],[1,3]]
    Output: [[1,4],[2,4],[3,4]]
    Explanation: 
    The item with value = 1 occurs in items1 with weight = 1 and in items2 with weight = 3, total weight = 1 + 3 = 4.
    The item with value = 2 occurs in items1 with weight = 3 and in items2 with weight = 1, total weight = 3 + 1 = 4.
    The item with value = 3 occurs in items1 with weight = 2 and in items2 with weight = 2, total weight = 2 + 2 = 4.
    Therefore, we return [[1,4],[2,4],[3,4]].
    

    Example 3:

    Input: items1 = [[1,3],[2,2]], items2 = [[7,1],[2,2],[1,4]]
    Output: [[1,7],[2,4],[7,1]]
    Explanation:
    The item with value = 1 occurs in items1 with weight = 3 and in items2 with weight = 4, total weight = 3 + 4 = 7. 
    The item with value = 2 occurs in items1 with weight = 2 and in items2 with weight = 2, total weight = 2 + 2 = 4. 
    The item with value = 7 occurs in items2 with weight = 1, total weight = 1.
    Therefore, we return [[1,7],[2,4],[7,1]].
    

      Constraints:

    Solution (Java)

    class Solution {
        public List<List<Integer>> mergeSimilarItems(int[][] arr1, int[][] arr2) {
            int[] cache = new int[1001];
            for (int[] num : arr1) {
                cache[num[0]] += num[1];
            }
            for (int[] num : arr2) {
                cache[num[0]] += num[1];
            }
            List<List<Integer>> result = new ArrayList<>();
            for (int i = 0; i < cache.length; i++) {
                int weight = cache[i];
                if (weight > 0) {
                    int value = i;
                    result.add(Arrays.asList(value, weight));
                }
            }
            return result;
        }
    }
    

    Explain:

    nope.

    Complexity: