Problem
Design your implementation of the circular double-ended queue (deque).
Implement the MyCircularDeque class:
MyCircularDeque(int k)Initializes the deque with a maximum size ofk.boolean insertFront()Adds an item at the front of Deque. Returnstrueif the operation is successful, orfalseotherwise.boolean insertLast()Adds an item at the rear of Deque. Returnstrueif the operation is successful, orfalseotherwise.boolean deleteFront()Deletes an item from the front of Deque. Returnstrueif the operation is successful, orfalseotherwise.boolean deleteLast()Deletes an item from the rear of Deque. Returnstrueif the operation is successful, orfalseotherwise.int getFront()Returns the front item from the Deque. Returns-1if the deque is empty.int getRear()Returns the last item from Deque. Returns-1if the deque is empty.boolean isEmpty()Returnstrueif the deque is empty, orfalseotherwise.boolean isFull()Returnstrueif the deque is full, orfalseotherwise.
Example 1:
Input
["MyCircularDeque", "insertLast", "insertLast", "insertFront", "insertFront", "getRear", "isFull", "deleteLast", "insertFront", "getFront"]
[[3], [1], [2], [3], [4], [], [], [], [4], []]
Output
[null, true, true, true, false, 2, true, true, true, 4]
Explanation
MyCircularDeque myCircularDeque = new MyCircularDeque(3);
myCircularDeque.insertLast(1); // return True
myCircularDeque.insertLast(2); // return True
myCircularDeque.insertFront(3); // return True
myCircularDeque.insertFront(4); // return False, the queue is full.
myCircularDeque.getRear(); // return 2
myCircularDeque.isFull(); // return True
myCircularDeque.deleteLast(); // return True
myCircularDeque.insertFront(4); // return True
myCircularDeque.getFront(); // return 4
Constraints:
1 <= k <= 10000 <= value <= 1000At most
2000calls will be made toinsertFront,insertLast,deleteFront,deleteLast,getFront,getRear,isEmpty,isFull.
Solution (Java)
class MyCircularDeque {
private final int[] data;
private int front;
private int rear;
private int size;
public MyCircularDeque(int k) {
data = new int[k];
front = 0;
rear = k - 1;
size = 0;
}
public boolean insertFront(int value) {
if (size == data.length) {
return false;
}
data[front] = value;
front = (front + 1) % data.length;
size++;
return true;
}
public boolean insertLast(int value) {
if (size == data.length) {
return false;
}
data[rear] = value;
rear = (rear - 1 + data.length) % data.length;
size++;
return true;
}
public boolean deleteFront() {
if (size == 0) {
return false;
}
front = (front - 1 + data.length) % data.length;
size--;
return true;
}
public boolean deleteLast() {
if (size == 0) {
return false;
}
rear = (rear + 1) % data.length;
size--;
return true;
}
public int getFront() {
if (size == 0) {
return -1;
}
return data[(front - 1 + data.length) % data.length];
}
public int getRear() {
if (size == 0) {
return -1;
}
return data[(rear + 1) % data.length];
}
public boolean isEmpty() {
return size == 0;
}
public boolean isFull() {
return size == data.length;
}
}
/**
* Your MyCircularDeque object will be instantiated and called as such:
* MyCircularDeque obj = new MyCircularDeque(k);
* boolean param_1 = obj.insertFront(value);
* boolean param_2 = obj.insertLast(value);
* boolean param_3 = obj.deleteFront();
* boolean param_4 = obj.deleteLast();
* int param_5 = obj.getFront();
* int param_6 = obj.getRear();
* boolean param_7 = obj.isEmpty();
* boolean param_8 = obj.isFull();
*/
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).