Problem
Given n
points
on a 2D plane where points[i] = [xi, yi]
, Return** the *widest vertical area* between two points such that no points are inside the area.**
A vertical area is an area of fixed-width extending infinitely along the y-axis (i.e., infinite height). The widest vertical area is the one with the maximum width.
Note that points on the edge of a vertical area are not considered included in the area.
Example 1:
Input: points = [[8,7],[9,9],[7,4],[9,7]]
Output: 1
Explanation: Both the red and the blue area are optimal.
Example 2:
Input: points = [[3,1],[9,0],[1,0],[1,4],[5,3],[8,8]]
Output: 3
Constraints:
n == points.length
2 <= n <= 10^5
points[i].length == 2
0 <= xi, yi <= 10^9
Solution (Java)
class Solution {
public int maxWidthOfVerticalArea(int[][] points) {
int[] xValues = new int[points.length];
for (int i = 0; i < points.length; i++) {
xValues[i] = points[i][0];
}
Arrays.sort(xValues);
int max = 0;
for (int j = 0; j < xValues.length - 1; j++) {
if (xValues[j + 1] - xValues[j] > max) {
max = xValues[j + 1] - xValues[j];
}
}
return max;
}
}
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).