1288. Remove Covered Intervals

Difficulty:
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    Problem

    Given an array intervals where intervals[i] = [li, ri] represent the interval [li, ri), remove all intervals that are covered by another interval in the list.

    The interval [a, b) is covered by the interval [c, d) if and only if c <= a and b <= d.

    Return the number of remaining intervals.

      Example 1:

    Input: intervals = [[1,4],[3,6],[2,8]]
    Output: 2
    Explanation: Interval [3,6] is covered by [2,8], therefore it is removed.
    

    Example 2:

    Input: intervals = [[1,4],[2,3]]
    Output: 1
    

      Constraints:

    Solution (Java)

    class Solution {
        public int removeCoveredIntervals(int[][] intervals) {
            Queue<int[]> q = new PriorityQueue<>((a, b) -> a[0] == b[0] ? b[1] - a[1] : a[0] - b[0]);
            for (int[] interval : intervals) {
                q.offer(interval);
            }
            int[] prev = q.poll();
            int count = 0;
            while (!q.isEmpty()) {
                int[] curr = q.poll();
                if (curr[0] >= prev[0] && curr[1] <= prev[1]) {
                    count++;
                } else {
                    prev = curr;
                }
            }
            return intervals.length - count;
        }
    }
    

    Explain:

    nope.

    Complexity: