970. Powerful Integers

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    Problem

    Given three integers x, y, and bound, return **a list of all the *powerful integers* that have a value less than or equal to** bound.

    An integer is powerful if it can be represented as xi + yj for some integers i >= 0 and j >= 0.

    You may return the answer in any order. In your answer, each value should occur at most once.

      Example 1:

    Input: x = 2, y = 3, bound = 10
    Output: [2,3,4,5,7,9,10]
    Explanation:
    2 = 20 + 30
    3 = 21 + 30
    4 = 20 + 31
    5 = 21 + 31
    7 = 22 + 31
    9 = 23 + 30
    10 = 20 + 32
    

    Example 2:

    Input: x = 3, y = 5, bound = 15
    Output: [2,4,6,8,10,14]
    

      Constraints:

    Solution (Java)

    class Solution {
        public List<Integer> powerfulIntegers(int x, int y, int bound) {
            int iBound = (x == 1 ? 1 : (int) (Math.log10(bound) / Math.log10(x)));
            int jBound = (y == 1 ? 1 : (int) (Math.log10(bound) / Math.log10(y)));
            HashSet<Integer> set = new HashSet<>();
            for (int i = 0; i <= iBound; i++) {
                for (int j = 0; j <= jBound; j++) {
                    int number = (int) (Math.pow(x, i) + Math.pow(y, j));
                    if (number <= bound) {
                        set.add(number);
                    }
                }
            }
            return new ArrayList<>(set);
        }
    }
    

    Explain:

    nope.

    Complexity: