2278. Percentage of Letter in String

Problem

Given a string s and a character letter, return** the percentage of characters in s that equal letter rounded down to the nearest whole percent.**

  Example 1:

Input: s = "foobar", letter = "o"
Output: 33
Explanation:
The percentage of characters in s that equal the letter 'o' is 2 / 6 * 100% = 33% when rounded down, so we return 33.

Example 2:

Input: s = "jjjj", letter = "k"
Output: 0
Explanation:
The percentage of characters in s that equal the letter 'k' is 0%, so we return 0.

  Constraints:

• 1 <= s.length <= 100

• s consists of lowercase English letters.

• letter is a lowercase English letter.

Solution (Java)

class Solution {
    public int percentageLetter(String s, char letter) {
        int count = 0;
        int n = s.length();
        for (int i = 0; i < n; i++) {
            if (s.charAt(i) == letter) {
                ++count;
            }
        }
        return (count * 100) / (n);
    }
}

Explain:

nope.

Complexity:

• Time complexity : O(n).
• Space complexity : O(n).