Problem
You are given an array rectangles
where rectangles[i] = [li, wi]
represents the ith
rectangle of length li
and width wi
.
You can cut the ith
rectangle to form a square with a side length of k
if both k <= li
and k <= wi
. For example, if you have a rectangle [4,6]
, you can cut it to get a square with a side length of at most 4
.
Let maxLen
be the side length of the largest square you can obtain from any of the given rectangles.
Return **the *number* of rectangles that can make a square with a side length of **maxLen
.
Example 1:
Input: rectangles = [[5,8],[3,9],[5,12],[16,5]]
Output: 3
Explanation: The largest squares you can get from each rectangle are of lengths [5,3,5,5].
The largest possible square is of length 5, and you can get it out of 3 rectangles.
Example 2:
Input: rectangles = [[2,3],[3,7],[4,3],[3,7]]
Output: 3
Constraints:
1 <= rectangles.length <= 1000
rectangles[i].length == 2
1 <= li, wi <= 10^9
li != wi
Solution (Java)
class Solution {
public int countGoodRectangles(int[][] rectangles) {
int maxSoFar = 0;
int count = 0;
for (int[] rectangle : rectangles) {
int sqLen = Math.min(rectangle[0], rectangle[1]);
if (maxSoFar <= sqLen) {
if (maxSoFar < sqLen) {
maxSoFar = sqLen;
count = 1;
} else {
count++;
}
}
}
return count;
}
}
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).