Problem
You are given an array rectangles where rectangles[i] = [li, wi] represents the ith rectangle of length li and width wi.
You can cut the ith rectangle to form a square with a side length of k if both k <= li and k <= wi. For example, if you have a rectangle [4,6], you can cut it to get a square with a side length of at most 4.
Let maxLen be the side length of the largest square you can obtain from any of the given rectangles.
Return **the *number* of rectangles that can make a square with a side length of **maxLen.
Example 1:
Input: rectangles = [[5,8],[3,9],[5,12],[16,5]]
Output: 3
Explanation: The largest squares you can get from each rectangle are of lengths [5,3,5,5].
The largest possible square is of length 5, and you can get it out of 3 rectangles.
Example 2:
Input: rectangles = [[2,3],[3,7],[4,3],[3,7]]
Output: 3
Constraints:
1 <= rectangles.length <= 1000rectangles[i].length == 21 <= li, wi <= 10^9li != wi
Solution (Java)
class Solution {
public int countGoodRectangles(int[][] rectangles) {
int maxSoFar = 0;
int count = 0;
for (int[] rectangle : rectangles) {
int sqLen = Math.min(rectangle[0], rectangle[1]);
if (maxSoFar <= sqLen) {
if (maxSoFar < sqLen) {
maxSoFar = sqLen;
count = 1;
} else {
count++;
}
}
}
return count;
}
}
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).