Problem
You are given a 0-indexed string s
of even length n
. The string consists of exactly n / 2
opening brackets '['
and n / 2
closing brackets ']'
.
A string is called balanced if and only if:
It is the empty string, or
It can be written as
AB
, where bothA
andB
are balanced strings, orIt can be written as
[C]
, whereC
is a balanced string.
You may swap the brackets at any two indices any number of times.
Return **the *minimum* number of swaps to make *s
balanced*.
Example 1:
Input: s = "][]["
Output: 1
Explanation: You can make the string balanced by swapping index 0 with index 3.
The resulting string is "[[]]".
Example 2:
Input: s = "]]][[["
Output: 2
Explanation: You can do the following to make the string balanced:
- Swap index 0 with index 4. s = "[]][][".
- Swap index 1 with index 5. s = "[[][]]".
The resulting string is "[[][]]".
Example 3:
Input: s = "[]"
Output: 0
Explanation: The string is already balanced.
Constraints:
n == s.length
2 <= n <= 10^6
n
is even.s[i]
is either'['
or']'
.The number of opening brackets
'['
equalsn / 2
, and the number of closing brackets']'
equalsn / 2
.
Solution (Java)
class Solution {
public int minSwaps(String s) {
int openCount = 0;
int swap = 0;
for (char c : s.toCharArray()) {
if (c == '[') {
openCount++;
} else {
if (openCount == 0) {
swap++;
openCount++;
} else {
openCount--;
}
}
}
return swap;
}
}
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).