Problem
You are given a 0-indexed integer array nums
.
We say that an integer x is expressible from nums
if there exist some integers 0 <= index1 < index2 < ... < indexk < nums.length
for which nums[index1] | nums[index2] | ... | nums[indexk] = x
. In other words, an integer is expressible if it can be written as the bitwise OR of some subsequence of nums
.
Return **the minimum *positive non-zero integer* that is not ****expressible from **nums
.
Example 1:
Input: nums = [2,1]
Output: 4
Explanation: 1 and 2 are already present in the array. We know that 3 is expressible, since nums[0] | nums[1] = 2 | 1 = 3. Since 4 is not expressible, we return 4.
Example 2:
Input: nums = [5,3,2]
Output: 1
Explanation: We can show that 1 is the smallest number that is not expressible.
Constraints:
1 <= nums.length <= 105
1 <= nums[i] <= 109
Solution (Java)
class Solution {
public int minImpossibleOR(int[] A) {
Set<Integer> s = new HashSet<>();
for (int a : A)
s.add(a);
int a = 1;
while (s.contains(a))
a <<= 1;
return a;
}
}
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).