860. Lemonade Change

Difficulty:
Related Topics:
Similar Questions:

    Problem

    At a lemonade stand, each lemonade costs $5. Customers are standing in a queue to buy from you and order one at a time (in the order specified by bills). Each customer will only buy one lemonade and pay with either a $5, $10, or $20 bill. You must provide the correct change to each customer so that the net transaction is that the customer pays $5.

    Note that you do not have any change in hand at first.

    Given an integer array bills where bills[i] is the bill the ith customer pays, return true if you can provide every customer with the correct change, or false otherwise.

      Example 1:

    Input: bills = [5,5,5,10,20]
    Output: true
    Explanation: 
    From the first 3 customers, we collect three $5 bills in order.
    From the fourth customer, we collect a $10 bill and give back a $5.
    From the fifth customer, we give a $10 bill and a $5 bill.
    Since all customers got correct change, we output true.
    

    Example 2:

    Input: bills = [5,5,10,10,20]
    Output: false
    Explanation: 
    From the first two customers in order, we collect two $5 bills.
    For the next two customers in order, we collect a $10 bill and give back a $5 bill.
    For the last customer, we can not give the change of $15 back because we only have two $10 bills.
    Since not every customer received the correct change, the answer is false.
    

      Constraints:

    Solution (Java)

    class Solution {
        public boolean lemonadeChange(int[] bills) {
            int countFive = 0;
            int countTen = 0;
            for (int bill : bills) {
                if (bill == 5) {
                    countFive++;
                } else if (bill == 10) {
                    if (countFive == 0) {
                        return false;
                    }
                    countFive--;
                    countTen++;
                } else if (bill == 20) {
                    if (countFive > 0 && countTen > 0) {
                        countFive--;
                        countTen--;
                    } else if (countFive >= 3) {
                        countFive -= 3;
                    } else {
                        return false;
                    }
                }
            }
            return true;
        }
    }
    

    Explain:

    nope.

    Complexity: