Problem
Given two strings s
and t
, return true
** if s
is a subsequence of t
, or false
otherwise**.
A subsequence of a string is a new string that is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (i.e., "ace"
is a subsequence of "abcde"
while "aec"
is not).
Example 1:
Input: s = "abc", t = "ahbgdc"
Output: true
Example 2:
Input: s = "axc", t = "ahbgdc"
Output: false
Constraints:
0 <= s.length <= 100
0 <= t.length <= 10^4
s
andt
consist only of lowercase English letters.
Follow up: Suppose there are lots of incoming s
, say s1, s2, ..., sk
where k >= 10^9
, and you want to check one by one to see if t
has its subsequence. In this scenario, how would you change your code?
Solution
class Solution {
public boolean isSubsequence(String s, String t) {
int i = 0;
int j = 0;
int n = t.length();
int m = s.length();
if (m == 0) {
return true;
}
while (j < n) {
if (s.charAt(i) == t.charAt(j)) {
i++;
if (i == m) {
return true;
}
}
j++;
}
return false;
}
}
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).