380. Insert Delete GetRandom O(1)

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Problem

Implement the RandomizedSet class:

You must implement the functions of the class such that each function works in average O(1) time complexity.

  Example 1:

Input
["RandomizedSet", "insert", "remove", "insert", "getRandom", "remove", "insert", "getRandom"]
[[], [1], [2], [2], [], [1], [2], []]
Output
[null, true, false, true, 2, true, false, 2]

Explanation
RandomizedSet randomizedSet = new RandomizedSet();
randomizedSet.insert(1); // Inserts 1 to the set. Returns true as 1 was inserted successfully.
randomizedSet.remove(2); // Returns false as 2 does not exist in the set.
randomizedSet.insert(2); // Inserts 2 to the set, returns true. Set now contains [1,2].
randomizedSet.getRandom(); // getRandom() should return either 1 or 2 randomly.
randomizedSet.remove(1); // Removes 1 from the set, returns true. Set now contains [2].
randomizedSet.insert(2); // 2 was already in the set, so return false.
randomizedSet.getRandom(); // Since 2 is the only number in the set, getRandom() will always return 2.

  Constraints:

Solution (Java)

class RandomizedSet {

    private final Random rand;
    private final List<Integer> list;
    private final Map<Integer, Integer> map;

    /* Initialize your data structure here. */
    public RandomizedSet() {
        this.rand = new Random();
        this.list = new ArrayList<>();
        this.map = new HashMap<>();
    }

    /* Inserts a value to the set. Returns true if the set did not already contain the specified element. */
    public boolean insert(int val) {
        if (map.containsKey(val)) {
            return false;
        }
        map.put(val, list.size());
        list.add(val);

        return true;
    }

    /* Removes a value from the set. Returns true if the set contained the specified element. */
    public boolean remove(int val) {
        if (!map.containsKey(val)) {
            return false;
        }
        int swap1 = map.get(val);
        int swap2 = list.size() - 1;
        int val2 = list.get(swap2);
        map.put(val2, swap1);
        map.remove(val);
        list.set(swap1, val2);
        list.remove(list.size() - 1);
        return true;
    }

    /* Get a random element from the set. */
    public int getRandom() {
        return list.get(rand.nextInt(list.size()));
    }
}

/**
 * Your RandomizedSet object will be instantiated and called as such:
 * RandomizedSet obj = new RandomizedSet();
 * boolean param_1 = obj.insert(val);
 * boolean param_2 = obj.remove(val);
 * int param_3 = obj.getRandom();
 */

Solution (Javascript)

/**
 * Initialize your data structure here.
 */
var RandomizedSet = function () {
  this.nums = new Array();
  this.locs = new Object();
};

/**
 * Inserts a value to the set. Returns true if the set did not already contain the specified element.
 * @param {number} val
 * @return {boolean}
 */
RandomizedSet.prototype.insert = function (val) {
  if (!(val in this.locs)) {
    this.nums.push(val);
    this.locs[val] = this.nums.length - 1;
    return true;
  }
  return false;
};

/**
 * Removes a value from the set. Returns true if the set contained the specified element.
 * @param {number} val
 * @return {boolean}
 */
RandomizedSet.prototype.remove = function (val) {
    if(val in this.locs) {
        let loc = this.locs[val];
        let lastEl = this.nums[this.nums.length - 1];
        this.nums[loc] = lastEl;
        this.locs[lastEl] = loc;
        this.nums.pop();
        delete this.locs[val];
        return true;
    }
    return false;
};

/**
 * Get a random element from the set.
 * @return {number}
 */
RandomizedSet.prototype.getRandom = function () {
    return this.nums[Math.floor(Math.random() * this.nums.length)];
};

Explain:

nope.

Complexity: