Problem
You are given a binary string s
consisting only of zeroes and ones.
A substring of s
is considered balanced if** all zeroes are before ones** and the number of zeroes is equal to the number of ones inside the substring. Notice that the empty substring is considered a balanced substring.
Return **the length of the longest balanced substring of **s
.
A substring is a contiguous sequence of characters within a string.
Example 1:
Input: s = "01000111"
Output: 6
Explanation: The longest balanced substring is "000111", which has length 6.
Example 2:
Input: s = "00111"
Output: 4
Explanation: The longest balanced substring is "0011", which has length 4.
Example 3:
Input: s = "111"
Output: 0
Explanation: There is no balanced substring except the empty substring, so the answer is 0.
Constraints:
1 <= s.length <= 50
'0' <= s[i] <= '1'
Solution (Java)
class Solution {
public int findTheLongestBalancedSubstring(String s) {
int max = 0;
for(int i = 0; i < s.length(); ){
int z = 0, o = 0;
while(i < s.length() && s.charAt(i) == '0') {
z++;
i++;
}
while(i < s.length() && s.charAt(i) =='1' && z > o){
o++;
i++;
max = Math.max(max, o*2);
}
while(i < s.length() && s.charAt(i) == '1') i++;
}
return max;
}
}
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).