2011. Final Value of Variable After Performing Operations

Difficulty:
Related Topics:
Similar Questions:

    Problem

    There is a programming language with only four operations and one variable X:

    Initially, the value of X is 0.

    Given an array of strings operations containing a list of operations, return **the **final **value of **X after performing all the operations.

      Example 1:

    Input: operations = ["--X","X++","X++"]
    Output: 1
    Explanation: The operations are performed as follows:
    Initially, X = 0.
    --X: X is decremented by 1, X =  0 - 1 = -1.
    X++: X is incremented by 1, X = -1 + 1 =  0.
    X++: X is incremented by 1, X =  0 + 1 =  1.
    

    Example 2:

    Input: operations = ["++X","++X","X++"]
    Output: 3
    Explanation: The operations are performed as follows:
    Initially, X = 0.
    ++X: X is incremented by 1, X = 0 + 1 = 1.
    ++X: X is incremented by 1, X = 1 + 1 = 2.
    X++: X is incremented by 1, X = 2 + 1 = 3.
    

    Example 3:

    Input: operations = ["X++","++X","--X","X--"]
    Output: 0
    Explanation: The operations are performed as follows:
    Initially, X = 0.
    X++: X is incremented by 1, X = 0 + 1 = 1.
    ++X: X is incremented by 1, X = 1 + 1 = 2.
    --X: X is decremented by 1, X = 2 - 1 = 1.
    X--: X is decremented by 1, X = 1 - 1 = 0.
    

      Constraints:

    Solution (Java)

    class Solution {
        public int finalValueAfterOperations(String[] operations) {
            int xValue = 0;
            for (String word : operations) {
                if (word.contains("+")) {
                    xValue++;
                } else {
                    xValue--;
                }
            }
            return xValue;
        }
    }
    

    Explain:

    nope.

    Complexity: