Problem
You are given an integer array nums
and two integers minK
and maxK
.
A fixed-bound subarray of nums
is a subarray that satisfies the following conditions:
- The minimum value in the subarray is equal to
minK
. - The maximum value in the subarray is equal to
maxK
.
Return the number of fixed-bound subarrays.
A subarray is a contiguous part of an array.
Example 1:
Input: nums = [1,3,5,2,7,5], minK = 1, maxK = 5
Output: 2
Explanation: The fixed-bound subarrays are [1,3,5] and [1,3,5,2].
Example 2:
Input: nums = [1,1,1,1], minK = 1, maxK = 1
Output: 10
Explanation: Every subarray of nums is a fixed-bound subarray. There are 10 possible subarrays.
Constraints:
2 <= nums.length <= 10^5
1 <= nums[i], minK, maxK <= 10^6
Solution (Java)
class Solution {
public long countSubarrays(int[] A, int minK, int maxK) {
long res = 0, jbad = -1, jmin = -1, jmax = -1, n = A.length;
for (int i = 0; i < n; ++i) {
if (A[i] < minK || A[i] > maxK) jbad = i;
if (A[i] == minK) jmin = i;
if (A[i] == maxK) jmax = i;
res += Math.max(0L, Math.min(jmin, jmax) - jbad);
}
return res;
}
}
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).