1400. Construct K Palindrome Strings

Difficulty:
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    Problem

    Given a string s and an integer k, return true **if you can use all the characters in *s* to construct k palindrome strings or false otherwise**.

      Example 1:

    Input: s = "annabelle", k = 2
    Output: true
    Explanation: You can construct two palindromes using all characters in s.
    Some possible constructions "anna" + "elble", "anbna" + "elle", "anellena" + "b"
    

    Example 2:

    Input: s = "leetcode", k = 3
    Output: false
    Explanation: It is impossible to construct 3 palindromes using all the characters of s.
    

    Example 3:

    Input: s = "true", k = 4
    Output: true
    Explanation: The only possible solution is to put each character in a separate string.
    

      Constraints:

    Solution (Java)

    class Solution {
        public boolean canConstruct(String s, int k) {
            if (s.length() == k) {
                // if size is same as k we can separate out all letters
                return true;
            }
            if (s.length() < k) {
                // if size is less than it is not possible
                return false;
            }
            // count occurrence of each letter
            int[] count = new int[26];
            for (char curr : s.toCharArray()) {
                count[curr - 'a']++;
            }
            // reduce k whenever count is odd
            for (int i = 0; i < 26; i++) {
                if (count[i] % 2 != 0) {
                    k--;
                }
            }
            // we can have max k odd characters
            return k >= 0;
        }
    }
    

    Explain:

    nope.

    Complexity: