Problem
You are given a 2D integer array ranges and two integers left and right. Each ranges[i] = [starti, endi] represents an inclusive interval between starti and endi.
Return true if each integer in the inclusive range [left, right] **is covered by *at least one* interval in** ranges. Return false otherwise.
An integer x is covered by an interval ranges[i] = [starti, endi] if starti <= x <= endi.
Example 1:
Input: ranges = [[1,2],[3,4],[5,6]], left = 2, right = 5
Output: true
Explanation: Every integer between 2 and 5 is covered:
- 2 is covered by the first range.
- 3 and 4 are covered by the second range.
- 5 is covered by the third range.
Example 2:
Input: ranges = [[1,10],[10,20]], left = 21, right = 21
Output: false
Explanation: 21 is not covered by any range.
Constraints:
1 <= ranges.length <= 501 <= starti <= endi <= 501 <= left <= right <= 50
Solution (Java)
class Solution {
public boolean isCovered(int[][] ranges, int left, int right) {
int[] temp = new int[52];
for (int[] range : ranges) {
int start = range[0];
int end = range[ranges[0].length - 1];
temp[start] += 1;
temp[end + 1] += -1;
}
for (int i = 1; i < temp.length; i++) {
temp[i] += temp[i - 1];
}
for (int i = left; i <= right; i++) {
if (temp[i] == 0) {
return false;
}
}
return true;
}
}
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).