Problem
An array nums of length n is beautiful if:
numsis a permutation of the integers in the range[1, n].For every
0 <= i < j < n, there is no indexkwithi < k < jwhere2 * nums[k] == nums[i] + nums[j].
Given the integer n, return **any *beautiful* array nums of length **n. There will be at least one valid answer for the given n.
Example 1:
Input: n = 4
Output: [2,1,4,3]
Example 2:
Input: n = 5
Output: [3,1,2,5,4]
Constraints:
1 <= n <= 1000
Solution (Java)
class Solution {
private Map<Integer, int[]> memo;
public int[] beautifulArray(int n) {
memo = new HashMap<>();
return helper(n);
}
private int[] helper(int n) {
if (n == 1) {
memo.put(1, new int[] {1});
return new int[] {1};
}
if (memo.containsKey(n)) {
return memo.get(n);
}
int mid = (n + 1) / 2;
int[] left = helper(mid);
int[] right = helper(n - mid);
int[] rst = new int[n];
for (int i = 0; i < mid; i++) {
rst[i] = left[i] * 2 - 1;
}
for (int i = mid; i < n; i++) {
rst[i] = right[i - mid] * 2;
}
memo.put(n, rst);
return rst;
}
}
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).