2695. Array Wrapper

Problem

Create a class ArrayWrapper that accepts an array of integers in its constructor. This class should have two features:

• When two instances of this class are added together with the + operator, the resulting value is the sum of all the elements in both arrays.
• When the String() function is called on the instance, it will return a comma separated string surrounded by brackets. For example, [1,2,3].

Example 1:

Input: nums = [[1,2],[3,4]], operation = "Add"
Output: 10
Explanation:
const obj1 = new ArrayWrapper([1,2]);
const obj2 = new ArrayWrapper([3,4]);
obj1 + obj2; // 10

Example 2:

Input: nums = [[23,98,42,70]], operation = "String"
Output: "[23,98,42,70]"
Explanation:
const obj = new ArrayWrapper([23,98,42,70]);
String(obj); // "[23,98,42,70]"

Example 3:

Input: nums = [[],[]], operation = "Add"
Output: 0
Explanation:
const obj1 = new ArrayWrapper([]);
const obj2 = new ArrayWrapper([]);
obj1 + obj2; // 0

Constraints:

• 0 <= nums.length <= 1000
• 0 <= nums[i]&nbsp;<= 1000
• Note: nums is the array passed to the constructor

Solution (Javascript)

/**
 * @param {number[]} nums
 */
var ArrayWrapper = function (nums) {
  this.nums = nums;
};

ArrayWrapper.prototype.valueOf = function () {
  return this.nums.reduce((sum, num) => sum + num, 0);
};

ArrayWrapper.prototype.toString = function () {
  return `[${this.nums.join(",")}]`;
};

/**
 * const obj1 = new ArrayWrapper([1,2]);
 * const obj2 = new ArrayWrapper([3,4]);
 * obj1 + obj2; // 10
 * String(obj1); // "[1,2]"
 * String(obj2); // "[3,4]"
 */

Explain:

nope.

Complexity:

• Time complexity : O(n).
• Space complexity : O(n).